Finding maximum curvature on lnx

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Homework Statement



Determine the point on a plane curve f(x) = ln x where the curvature is maximum.[/B]

Homework Equations



k(x) = || T ' (x) || / || r ' (x ) ||

k (x) = f '' (x) / [ 1 + ( f '' (x))2 ] 3/2[/B]

The Attempt at a Solution



f ' (x) = 1/x
f " (x) = -1/x2

k(x) = 1/x2 / { [1 + (1/x)2 ] 3/2 }

k(x) = 1/x2 / { [ x2 +1 /x2 ] 3/2 }

iirc we can use the first derivative and try to find the local max...but how do we even start it with this mess? quotient rule? Maybe there's something about the problem that tells us its impossible...? I'm lost here...
 
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tensor0910 said:

Homework Statement



Determine the point on a plane curve f(x) = ln x where the curvature is maximum.[/B]

Homework Equations



k(x) = ιι T ' (x) ιι / ιι r ' (x ) [/B]
There's a lot of extra stuff that I can't read in your formula above. What are these characters? ιι
tensor0910 said:

k (x) = ι f '' (x) ι / [ 1 + ( f '' (x))2 ] 3/2
And what's this one? ι
tensor0910 said:

The Attempt at a Solution



f ' (x) = 1/x
f " (x) = 1/x2
You lost a sign here (above).
tensor0910 said:
k(x) = 1/x2 / { [1 + (1/x)2 ] 3/2 }

k(x) = 1/x2 / { [ x2 +1 /x2 ] 3/2 }

iirc we can use the first derivative and try to find the local max...but how do we even start it with this mess? quotient rule? Maybe there's something about the problem that tells us its impossible...? I'm lost here...
Sure, quotient rule would work, provided you are careful and methodical. It would be helpful to simplify the expression as much as possible for attempting to differentiate it.
 
I cleaned it up a bit. Sorry!
 
tensor0910 said:

Homework Statement



Determine the point on a plane curve f(x) = ln x where the curvature is maximum.[/B]

Homework Equations



k(x) = || T ' (x) || / || r ' (x ) ||

k (x) = f '' (x) / [ 1 + ( f '' (x))2 ] 3/2[/B]

The Attempt at a Solution



f ' (x) = 1/x
f " (x) = -1/x2

k(x) = 1/x2 / { [1 + (1/x)2 ] 3/2 }

k(x) = 1/x2 / { [ x2 +1 /x2 ] 3/2 }

iirc we can use the first derivative and try to find the local max...but how do we even start it with this mess? quotient rule? Maybe there's something about the problem that tells us its impossible...? I'm lost here...
There are some mistakes in your formulas.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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