Minimum Speed for Daredevil to Jump 11m Canyon on 15 Degree Incline

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To determine the minimum speed a daredevil must achieve to jump an 11 m wide canyon from a 15-degree incline, the problem requires analyzing motion in two dimensions. The equations of motion, including Vf^2 = 2a(delta d) + Vi^2 and Vf = at + Vi, are essential for calculations. It's crucial to establish the initial velocity and the trajectory to calculate the horizontal distance covered during the jump. By setting up the equations based on the initial velocity and constants, one can derive the necessary speed to clear the canyon. Understanding these principles is vital for solving the problem effectively.
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A daredevil jumps a canyon 11 m wide. To do so, he drives a car up a 15 degree incline.
Acceleration of gravity = 9.81 m/s^2
What minimum speed must he achieve to clear the canyon in m/s?

Homework Equations



Vf^2 = 2a(delta d) + Vi^2

Vf = at + Vi
 
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missashley said:
A daredevil jumps a canyon 11 m wide. To do so, he drives a car up a 15 degree incline.
Acceleration of gravity = 9.81 m/s^2
What minimum speed must he achieve to clear the canyon in m/s?

Homework Equations



Vf^2 = 2a(delta d) + Vi^2

Vf = at + Vi

You are going to need a bit more than this to solve the problem: if there is jumping or throwing involved, you are usually going to need to look at the motion in two dimensions. What do you need to set this problem up? How do you describe where this person starts, where they're supposed to try to land, and how they traveled in between?
 
Heres an idea: assume you know the velocity he took off. Now find out how far he traveled. Create an equation for it to only be in terms of his initial velocity, distance traveled and other constants. Then work backwards from here and find his velocity knowing how far he has to travel.
 

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