Finding out force from a relation of position

AI Thread Summary
To find the force exerted on a 1kg particle with position x = t(t-1)(t-2) m, the correct approach involves differentiating the position function twice to obtain acceleration. The user initially calculated acceleration as a = 4t - 6 but later realized their mistake and corrected their solution. The force can then be determined using Newton's second law, F = ma, where m is the mass of the particle. The discussion highlights the importance of careful differentiation in solving physics problems. Ultimately, the user resolved their confusion and successfully found the correct force values.
Vv anand
Messages
41
Reaction score
1

Homework Statement



A particle of 1kg loves along x acid such that it's position x varies with time t as x =t(t-1)(t-2) m find the force exerted on the particle at t=0,1,2

Homework Equations


Just given that position x varies with time t as x=t(t-1)(t-2)

The Attempt at a Solution


After opening the bracket, i tried to differentiate it twice to get relation of acceleration but the answer i m getting is incorrect...I m getting a=4t-6 am i correct?
 
Physics news on Phys.org
I just tried to solve it again and i solved it nvm..Thx
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top