Finding Phase Difference in an RC circuit

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SUMMARY

The discussion focuses on calculating the phase difference in an RC circuit using complex impedance. The user successfully determined the input impedance as ##Z_{in} = 5\Omega - 3.97j \Omega## and the magnitude of impedance as ##Z = 6.83 \Omega##, leading to a current of ##I_m = 1.57A## and a phase angle of ##\phi = -38.4^o##. However, the user is uncertain about how to find the second phase angle needed to calculate the phase difference (##\Delta \phi##), as no additional phase value is provided in the problem statement.

PREREQUISITES
  • Understanding of complex impedance in AC circuits
  • Familiarity with Ohm's law in the context of AC analysis
  • Knowledge of phasor representation and polar notation
  • Basic concepts of RC circuit behavior
NEXT STEPS
  • Learn how to calculate phase angles in AC circuits using phasor analysis
  • Study the application of the formula ##\phi = arctan(\frac{-1/\omega C}{R})## in different scenarios
  • Explore the use of complex numbers in electrical engineering, particularly in circuit analysis
  • Investigate methods for determining phase differences in multi-component AC circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits, particularly those working with RC circuits and phase relationships.

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Homework Statement


2f81f751582010247d94b5e5d9a53c5a.png


Homework Equations


##V = ZI##
##Z_R = R##
##Z_C = -\frac{j}{\omega C}##
##Z = \sqrt{R^2 + (\frac{1}{\omega C})^2}##
##P_{av} = \frac{1}{2}V_m I_m cos(\phi)##
##\phi = arctan(\frac{-1/\omega C}{R})##
##\Delta \phi = \phi _1 -\phi _2##

The Attempt at a Solution


I've found what I believe to be the solution to the first part ##Z_{in} = Z_R + Z_C = 5\Omega - 3.97j \Omega## and the admittance which is ##Y = \frac{1}{Z}##

For part b, I calculated the magnitude of Z and got ##Z = 6.83 \Omega ## and then found the current using ##I_m = \frac{V_m}{Z}## = 1.57A. I calculated ##\phi = -38.4^o## and got a power of ##6.15W##.

For part c, I'm stuck on finding the phase difference (##\Delta \phi##) because I'm not sure how to find another value of ##\phi## and there is none specified in the question. Any help would be appreciated.
 
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Ii = Io = Vi/(R - j/ωC)

Vo = Io * ( -j/ωC )

Phase shift = Φ , where Φ is calculated from Vo/Vi = xxxx∠Φ ( result in polar notation )

You may find an easier way, but this is the "basic" method.
 
Last edited:

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