Finding region bounded by curves

  • Thread starter Thread starter superelf83
  • Start date Start date
  • Tags Tags
    Bounded Curves
Click For Summary
SUMMARY

The discussion centers on finding the area of the region bounded by the curves y = x + 1, y = e^(-x), and the vertical line x = 1. The intersection points of these curves are identified as (0, 1) for y = x + 1 and y = e^(-x), (1, 2) for y = x + 1 and x = 1, and (1, e^(-1)) for y = e^(-x) and x = 1. The area can be calculated using the integral from 0 to 1 of the difference between the two functions, yielding the expression ∫_0^1 (x + 1 - e^(-x)) dx.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with functions and their intersections
  • Knowledge of exponential functions, specifically e^(-x)
  • Ability to evaluate definite integrals
NEXT STEPS
  • Study the method of finding intersection points of curves
  • Learn about definite integrals and their applications in area calculation
  • Explore the properties of exponential functions and their graphs
  • Practice solving similar problems involving bounded regions
USEFUL FOR

Students in calculus, educators teaching integral calculus, and anyone interested in understanding the geometric interpretation of integrals and area calculations between curves.

superelf83
Messages
5
Reaction score
0
Hi. I'm new here. :) I was wondering if anyone could help me out with this problem...
i'm supposed to find the region bounded by:
y=x+1
y=e^-x
x=1

i think i should find the other point of intersection but i forgot to do that (i haven't taken a math course for about 4 years).
please help!
 
Physics news on Phys.org
It's just

\int_0^1 (x+1-e^{-x}) dx = (\frac 1 2 x^2 + x + e^{-x})\vert_0^1 = 1/2+e^{-1}
 
Find the region or find the area of the region?

"i think i should find the other point of intersection but i forgot to do that "
Forgot to do that or forgot how to do that?:rolleyes:

The region is bounded by the three curves y= x+ 1, y= e-x and x= 1. It should be easy to see that y= x+ 1 and y= e-x cross at (0, 1). Of course, y= x+ 1 and x= 1 cross at (1, 2). Finally, y= e-x and x= 1 cross at (1, e-1).

maverick6664, please don't give the full answer to homework problems.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K