Finding resistivity experimentally

  • Thread starter Thread starter nokia8650
  • Start date Start date
  • Tags Tags
    Resistivity
Click For Summary
SUMMARY

The discussion centers on the experimental determination of resistivity using the formula ρ = AR/L, where L represents the length of the wire. Participants confirm that, theoretically, the current (I) remains constant as the length (L) varies, provided that the cross-sectional area (A) and resistivity (ρ) are unchanged. The voltage (V) increases proportionally with length, maintaining a constant current under ideal conditions. However, practical considerations regarding the finite resistance of the voltmeter may introduce slight variations in current.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Familiarity with the concept of resistivity (ρ) and its formula
  • Knowledge of how to manipulate electrical measurements using crocodile clips
  • Basic principles of circuit theory, including voltage and current relationships
NEXT STEPS
  • Research the impact of voltmeter resistance on current measurement accuracy
  • Explore practical experiments to measure resistivity using different materials
  • Learn about the limitations of ideal vs. real-world electrical components
  • Investigate advanced techniques for measuring current in varying circuit conditions
USEFUL FOR

Students and educators in physics, electrical engineering professionals, and anyone conducting experiments related to electrical resistivity and circuit analysis.

nokia8650
Messages
216
Reaction score
0
See: http://img229.imageshack.us/img229/5353/cirlm2.th.jpg

L is varied by moving the crocodile clips along the wire.

Am I right in thinking that the current flowing will remain the same irrespective of the length?

My reasoning:

rho=AR/L
R=V/I

sub and rearrange to give:

I=AV/L(rho)

As L increases, V increases by the same proportion. A and rho remain constant. Thus, I is constant.

Thanks
 
Last edited by a moderator:
Physics news on Phys.org
What is L? You did not even specify it in the image...

I am going to assume you are changing the position of the 'arrow' on the black wire, effectively measuring a different voltage?

Then I believe yes, theoretically, the current will remain the same since an ideal voltage meter (what's the word?) has an infinite resistance. (So no current will flow through the 'shortcut' with the voltage meter)

In practice, it will obviously have a finite (but very large) resistance and the current might change a little, but this will probably be very small.
 
Hi, sorry for not defining the symbols. L was the length, and thanks, as you answered my question despite me being unclear!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
Replies
44
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
7
Views
1K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
170
Views
9K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K