Finding Riemann Integrability for f(x) on [0,1]

Silviu
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Homework Statement


Find a such that f is Riemann integrable on [0,1], where:
##f = x^acos(1/x)##, x>0 and f(0) = 0

Homework Equations

The Attempt at a Solution


I found at previous points a such that f is continuous, bounded and derivable, but I am not sure how to use that (as all these implications work just one way). Also the definition with partitions seems hard to use here. Any hint?
 
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Silviu said:
I found at previous points a such that f is continuous, bounded and derivable, but I am not sure how to use that (as all these implications work just one way).
You should have a statement "a function is Riemann integrable if it is [...]" that helps with all a where it is integrable. For the rest you'll have to see how to show that it is not.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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