Finding Solutions for Sin 2θ = Sin θ in the Interval 0 ≤ θ ≤ 360?

AI Thread Summary
To solve the equation sin 2θ = sin θ for 0 ≤ θ ≤ 360, the identity sin 2θ = 2sinθcosθ is applied. By rearranging the equation to 2sinθcosθ - sinθ = 0, it can be factored to sinθ(2cosθ - 1) = 0. This yields solutions where sinθ = 0, giving θ values of 0, 180, and 360 degrees, and where 2cosθ - 1 = 0, resulting in θ values of 60 and 300 degrees. Thus, the complete set of solutions is θ = 0, 60, 180, 300, and 360 degrees. The approach taken appears correct for finding these angles.
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Homework Statement



Find all values of θ in the interval 0 ≤ θ ≤ 360 that satisfy the equation sin 2θ = sin θ

Homework Equations



sin2θ = 2sinAcosA

The Attempt at a Solution



I'm a little confused on how to start off knowing sin2θ is equivalent to 2sinAcosA, would you factor this?
 
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sin2A = SinA
2SinAcosA = SinA
2SinAcosA - SinA = 0
SinA (2CosA-1)= 0
sinA = 0 2CosA-1=0
A= 0,180,360 A= 60, 300

i didn't check this, i just did this real quick, if i was wrong sorry, but i think i did it right
Hope that helps
 


Thanks a lot for this :)
 
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