Finding Speed & Momentum of a Moving Particle with Double Rest Mass

AI Thread Summary
A moving particle has a rest mass that is double its kinetic energy, leading to a discussion on how to find its speed and momentum using relativity principles. The problem is considered basic for those familiar with advanced physics, suggesting that understanding classical mechanics is essential for tackling it. Participants emphasize the importance of applying the correct formulas and encourage sharing any specific difficulties encountered. The relationship between rest mass and kinetic energy is highlighted, with a focus on using the equation m₀c² = 2E_k. Overall, the discussion aims to clarify the problem-solving process in relativity.
hype_chicky
Messages
34
Reaction score
0
a moving particle has a rest mass which is double its kinetic energy. Find its speed and momentum..=)
 
Physics news on Phys.org
this is the most basic problem in relativity... are you having a hard time understanding relativity or you just can't figure out how to do this problem...
relativity usually puts in a advance physics class. since you are learning relativity now, i believe you have already suffer through the classical mechanic and electrostatic and thermal physics those basic stuff... and you have already develope a skill to deal with physics problems. This problem is not tricky at all. plug the number in appropiate formulas and the answer will shown up instantly... if you really can't do this problem, at least show me some of your work or let me know which part you stuck in...
 
okay so the rest mass is doubel the kinetic energy so i have Ek = mc^2/ sqare root 1-V^2/C^2 - mc^2...yet once agnin i DO NOT understand how to fit it in..as u can see physics is not one of my favourite classes =)
 
Okay.So its rest mass (mulitplied by c^squared to give energy) is 2 times greater than the KE.Can u write the RHS from this equation?
m_{0}c^{2}=2...

What should be instead of those points...??

Daniel.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top