Finding the Angle of Motion After an Impulse

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In summary, the problem involves particles A, B, and C connected by strings and lying at rest on a smooth horizontal plane. A receives an impulse directed away from B and C along the bisector of angle BAC, causing A to start moving at an angle alpha to the direction of the impulse. The equation for alpha is given as tan(alpha) = 2sin(theta)/6-3cos(theta). To solve this problem, we need to consider the direction of velocity for B and C after the impulse, the constraint condition relating the velocity of A to B and C, and the total linear momentum of the system after the impulse.
  • #1
jiayingsim123
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Homework Statement


A particle A, of mass 3kg, is connected by light, inextensible strings to particles B and C, of masses 5kg and 1kg respectively. They lie at rest on a smooth horizontal plane, with the strings just taut and angle BAC=theta. A then receives and impulse directed away from B and C along the bisector of the angle BAC.Show that A starts to move at an angle alpha to the direction of the impulse, where

tan (alpha) = 2 sin (theta)/6-3cos(theta)

Please provide detailed explanations along with your answer, thanks in advance! :D


Homework Equations





The Attempt at a Solution


Sorry I don't even know where to start! Please help me with this question, thanks in advance! :)
 
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  • #2
Oh goodie, another stringy problem :-p. Ok, some things to consider:

1. What is the direction of the velocity of B after the impulse? of C?
2. There is an important constraint condition relating the velocity of A and the velocity of B after the impulse. What is it? Can you express it mathematically? Similarly for A and C.
3. What can you say about the total linear momentum of the system after the impulse? In particular, what is the value of the component of the total momentum in a direction that’s perpendicular to the impulse?
 

Related to Finding the Angle of Motion After an Impulse

1. What is impulsive tension?

Impulsive tension is a force that occurs suddenly and has a very short duration. It is often caused by a sudden change in acceleration or velocity, such as a collision or explosion.

2. How is impulsive tension different from static tension?

Unlike static tension, which is a steady force over a period of time, impulsive tension is a sudden force that occurs over a very short period of time. This can make it more difficult to predict and analyze, as it may only affect a system for a brief moment.

3. What are some real-life examples of impulsive tension?

Impulsive tension can be observed in many everyday situations, such as a person jumping off a high dive, a car coming to a sudden stop, or a hammer hitting a nail. It is also a common force in more extreme situations, like rocket launches or explosions.

4. How is impulsive tension calculated?

The calculation of impulsive tension depends on the specific situation and the forces involved. In general, it can be calculated using the formula F = mΔv/Δt, where F is the impulsive tension, m is the mass of the object, Δv is the change in velocity, and Δt is the duration of the force.

5. What are some potential effects of impulsive tension on a system or object?

Impulsive tension can have a variety of effects on a system or object, depending on its magnitude and direction. It can cause objects to move, deform, or break. It can also lead to changes in the kinetic or potential energy of a system. In extreme cases, impulsive tension can cause damage or destruction.

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