Finding the Aperture Size for 1-Arcsec Resolution at 500nm Wavelength

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AI Thread Summary
To achieve 1-arcsecond resolution at a wavelength of 500 nm, the required aperture size can be calculated using the formula d = wavelength/theta. Converting 1 arcsecond to radians gives approximately 5 x 10^-6 radians. Substituting these values into the equation results in an aperture size of 0.1 meters. This calculation confirms that a 10 cm aperture is necessary for the desired resolution. The solution appears accurate based on the provided parameters.
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Homework Statement




What apeture is required to give 1-arcsec resolution for a wavelength of 500 nm(visible)

Homework Equations



theta=wavelength/d ; d is the size of the apeture

The Attempt at a Solution


I'm assuming when they are asking for the apeture , they are asking for the size of the apeture.

theta=wavelength/d => d=wavelength/theta =

I converted 1 arc second to 5*10^-6 radian

d=500*10^-9 m/5*10^-6= .1 m
 
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Looks right to me.
 

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