Finding the change in length of a nylon string

AI Thread Summary
A nylon tennis string under a tension of 225 N and with a diameter of 0.97 mm is being analyzed for its change in length from an initial length of 29.6 cm. The area of the string was calculated, and the Young's Modulus for nylon was confirmed to be 5 x 10^9 N/m². After several incorrect attempts, the correct change in length was determined to be approximately 1.8025 cm, which is a more reasonable value than previous calculations. The final answer was confirmed to be in centimeters after multiplying the result from the formula. The discussion highlights the importance of careful calculations and unit conversions in physics problems.
tjohn101
Messages
92
Reaction score
0

Homework Statement


A nylon tennis string on a racket is under a tension of 225 N. If its diameter is 0.97 mm, by how much is it lengthened from its untensioned length of 29.6 cm?

Li= 29.6cm =.296 m
r= 4.85e-4 m
A= 7.389811319e-7
F= 225 N
E= Young's Modulus for Nylon= 5 x 10^9
Solving for deltaL

Homework Equations


A=pi(r)^2
F= E (delta L/Li) A

The Attempt at a Solution


I've found the area and tried using the equation above but did not get a correct answer. I may well have messed up the calculations because that equation confuses me a little and I seem to be algebraically challenged this fine morning.
All my incorrect answers so far are:
14.5e-8 cm
7.470483757e-8 cm
14.506204362e-7 cm
7.470483757e-6 cm (the last three answers came from the equation above)

Any help is greatly appreciated! Thank you!
 
Physics news on Phys.org
\Delta L = \frac{FL}{AE}


what units are E in?
 
rock.freak667 said:
\Delta L = \frac{FL}{AE}


what units are E in?

I've been trying to find the equation in latex... :/ E is in N/m^2.
 
tjohn101 said:
I've been trying to find the equation in latex... :/ E is in N/m^2.

I was just checking to see what units the value of E you quoted were in.

But try plugging the number back in and checking again, you aren't supposed to get such small changes in length.
 
rock.freak667 said:
I was just checking to see what units the value of E you quoted were in.

But try plugging the number back in and checking again, you aren't supposed to get such small changes in length.

Okay I plugged everything into it and got an answer but I need to be sure it's right. I only have one more try. :/ Would the answer be 1.802481745?

PS: I love your signature. Makes everything so much simpler. : )
 
tjohn101 said:
Okay I plugged everything into it and got an answer but I need to be sure it's right. I only have one more try. :/ Would the answer be 1.802481745?

If you mean 1.8025 cm, then I believe so as that looks better than 14.506204362x10-7 cm
 
rock.freak667 said:
If you mean 1.8025 cm, then I believe so as that looks better than 14.506204362x10-7 cm

Where did that answer come from? And sorry about the long numbers. My homework website is extremely picky
 
tjohn101 said:
Where did that answer come from? And sorry about the long numbers. My homework website is extremely picky

1.802481745 what unit is this in?

for the other number, I just quoted one of your above answers.
 
rock.freak667 said:
1.802481745 what unit is this in?

for the other number, I just quoted one of your above answers.

Centimeters. The final answer is supposed to be in centimeters so I multiplied the answer from the equation by 100.

Oh yeah I forgot about that one. :/ That was early this morning.
 
  • #10
tjohn101 said:
Centimeters. The final answer is supposed to be in centimeters so I multiplied the answer from the equation by 100.

Oh yeah I forgot about that one. :/ That was early this morning.

then 1.802481745cm should be it.
 
  • #11
rock.freak667 said:
then 1.802481745cm should be it.

That it is! Thank you very much for your help, sir.
 
Back
Top