Finding the Density of a Solid Object in Water

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To find the density of a solid object submerged in water, first calculate the buoyant force using the difference between the object's weight in air and its weight in water. The buoyant force is equal to the weight of the water displaced, which can be expressed as the product of the water's density, the volume of the object, and gravitational acceleration. By applying Archimedes' Principle, the volume of the object can be derived from the buoyant force. Once the volume is known, the density can be calculated using the formula density equals mass divided by volume. This approach effectively combines the concepts of buoyancy and density to solve the problem.
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Homework Statement


A solid object has a weight of 17.22 N. When it is suspended from a scale and submerged in water, the scale reads 5.18 N. Find the density of the object (use ρwater = 1000 kg/m3).


Homework Equations


p = m/v


The Attempt at a Solution


I don't know how to figure this out without having the volume? Or does it have something to do with buoyant forces??
 
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If I use the buoyant force equation...
Fb = Po * Vo * g
then solve for V?
 
What is Po? If you use Archimedes' Principle, you'll get it immdtly. Refer to your other post. That's why I asked you to state it, at least.
 
Po is density of the object.
 
The reduction in force is equal to the upward buoyant force, which I have shown how to find in your other post.
 

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