Finding the Derivative of a Square Root Function

gomes.
Messages
58
Reaction score
0
function --- derivative (help!)

Homework Statement




[PLAIN]http://img15.imageshack.us/img15/705/123gm.jpg

but instead of f(x)=x^-2, let f(x) = x^(1/2 )


The Attempt at a Solution




So, I did

[ (x+h)^1/2 - (x)^1/2 ]/ h

But I am not sure how to simplify it. What would be my next step? Thanks a lot :)
 
Last edited by a moderator:
Physics news on Phys.org


gomes. said:

Homework Statement




[PLAIN]http://img15.imageshack.us/img15/705/123gm.jpg

but instead of f(x)=x^-2, let f(x) = x^(1/2 )


The Attempt at a Solution




So, I did

[ (x+h)^1/2 - (x)^1/2 ]/ h

But I am not sure how to simplify it. What would be my next step? Thanks a lot :)

Rationalize the numerator. (Like rationalizing the denominator, only opposite) :cool:
 
Last edited by a moderator:


Ah okay, yea I got it now. thanks :)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top