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Finding the determinent or the identity of the matrix?

  1. Mar 10, 2005 #1
    I have the following problem:

    Let C= | 1 2 3 |
    | 2 5 3 |
    | 1 0 8 |

    and D = | -40 16 a |
    | b -5 -3 |
    | 5 -2 -1 |

    Determine the values of and and b such that D = C^-1

    Do i start off by finding the determinent or the identity or whatever?
     
  2. jcsd
  3. Mar 10, 2005 #2

    xanthym

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    If D = C^(-1), then CD = I, where I is the identity matrix. Multiply C and D to produce another 3x3 matrix and determine values for "a" and "b" such that this product has "1" for diagonal elements and "0" elsewhere. Take your time with the product so you don't make careless mistakes. If done correctly, the answer will be quite apparent.


    ~~
     
    Last edited: Mar 10, 2005
  4. Mar 10, 2005 #3
    I got the product of CD to be:

    13 0 a-9
    -35 1 2a-18
    0 0 a-8

    I multiplied that by I and got the same number. What do I do now?

    Cheers
     
  5. Mar 10, 2005 #4

    xanthym

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    What happened to "b"?? The variable "b" should appear in your product CD (just like "a" appears in CD). First multiply C & D correctly, then choose values of "a" & "b" such that diagonal elements are "1" and all others are "0". It should be quite apparent!!
    (Note: Do not multiply by "I". You want CD to BE "I" after selecting proper values for "a" and "b".)


    ~~
     
    Last edited: Mar 10, 2005
  6. Mar 10, 2005 #5
    Thanks for the help. I get:

    2b-25 0 a-9
    5b-65 1 2a-18
    0 0 a-8

    So does that mean b= 13 and a=9 if you want the diagonals to be 1?

    Thanks,
     
  7. Mar 10, 2005 #6

    xanthym

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    CORRECT. That's exactly how to solve the problem.
     
  8. Mar 10, 2005 #7
    Muchly appreciated man. Thank you :!!)
     
  9. Mar 11, 2005 #8

    BobG

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    Homework Helper

    Actually, you could have just found the inverse of the original matrix. Then the value of a and b would also be obvious.

    There's at least three ways to find the inverse matrix:

    The elimination or pivot method.

    The determinant method .

    The Cayley-Hamilton method (unfortunately, I can't find a good link that really breaks this one out - I have a book, Quaternions and Rotation Sequences by Jack Kuipers, that breaks this out so well even a beginner can understand it).
    Edit: Okay, even though text only, this isn't too bad: http://mathforum.org/library/drmath/view/51978.html

    There are also several other methods or variations. This link presents the first two in a different manner (Gaussian elimination and a LaPlace expansion).
    http://qucs.sourceforge.net/tech/node15.html

    The advantage of the determinant and the Cayley-Hamilton method is that you find out pretty quick whether or not there even is an inverse.
     
    Last edited: Mar 11, 2005
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