Finding the Dimensionally Consistent Powers for Acceleration Equation

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To determine the powers p and q for the equation A=V^p t^q that ensure dimensional consistency, the dimensions of acceleration (L^1 T^-2) must match the combined dimensions of velocity and time. The expression for velocity is L^1 T^-1, and time is represented as T. By substituting these into the equation, we find that (L^1 T^-1)^p (T)^q must equal L^1 T^-2. Solving the resulting equations for L and T gives p=1 and q=-2. This basic dimensionality problem illustrates the importance of matching dimensions in physics equations.
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Acceleration is related to velocity and time by the following expression: A=V^p t^q

Find the powers p and q that make this equation dimensionally consistent.
 
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You know that acceleration is L^1 T^-2, that velocity is L^1 T^-1 and t is of course T.

V^p t^q = (L^1 T^{-1})^p (T)^q = (L^1 T^{-2}) = A

this is your very basic dimensionality problem. Try to look over some examples and post your work if you need further help.
 
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