Finding the direction of current given a varying magnetic....

AI Thread Summary
The discussion revolves around applying Ampere's law to determine the direction of current in a magnetic field. It emphasizes that integration should be performed counterclockwise (CCW) around the loop, regardless of whether the magnetic field is increasing or decreasing. A positive result from the integral indicates that the current flows out of the page, while a negative result suggests it flows into the page. The direction of the differential length element (ds) is crucial for interpreting the results correctly. Overall, understanding the relationship between the magnetic field and current direction is key to solving the problem.
alexdr5398
Messages
31
Reaction score
1

Homework Statement


YZgf1wB.jpg


Homework Equations


μ0 In,e = ∫B⋅ds

The Attempt at a Solution


I really don't how to approach this question at all.

Do you have to integrate counterclockwise around the loop every time? If the field was decreasing as y decreased, would you integrate CW or is it still CCW?

Why does μ0 In,e = ∫B⋅ds being >0 mean that it must be out of the page.
 
Physics news on Phys.org
The direction of ##\vec {ds}## has a meaning. You go around in a mathematically positive direction (CCW).

Ampere's law is an integral form of one of the maxwelll equations.

If ##d\vec l## in the link (your ##\vec {ds}## ) goes around CCW then ##\vec {d\bf {S}}## is pointing towards you (the positive z direction).

If the field is decreasing you still go around CCW and you get a negative ##\vec I## -- i.e. pointing in the negative z direction.
 
  • Like
Likes alexdr5398
BvU said:
The direction of ##\vec {ds}## has a meaning. You go around in a mathematically positive direction (CCW).

Ampere's law is an integral form of one of the maxwelll equations.

If ##d\vec l## in the link (your ##\vec {ds}## ) goes around CCW then ##\vec {d\bf {S}}## is pointing towards you (the positive z direction).

If the field is decreasing you still go around CCW and you get a negative ##\vec I## -- i.e. pointing in the negative z direction.

Okay, I understand. Thank you.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top