Finding the displacement under a curve.

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Homework Help Overview

The discussion revolves around finding the displacement under a velocity-time curve between two time points, t=0 s and t=7 s. The original poster attempts to calculate the area under the curve, considering both positive and negative contributions based on the velocity values.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of calculating the area under the curve using geometric shapes such as rectangles, trapezoids, and triangles. Questions are raised about the original poster's calculations and the interpretation of the area relative to the horizontal axis.

Discussion Status

Some participants are seeking clarification on the original poster's calculations, while others suggest a reevaluation of how the area is determined in relation to the v=0 line. There is an ongoing exploration of the correct approach to finding the displacement.

Contextual Notes

The original poster mentions a lack of a graph to illustrate their calculations, which may affect the clarity of their reasoning. There is also an indication that the calculations provided may not align with the expected method for determining displacement.

kimberley511
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1. What is the displacement between t= 0 s and t= 7 s?The "area' under the curve, between the two times is the displacement. The "area" is the area enclosed by the curve and the time axis (v=0 line). Those parts of the curve with negative velocity contribute negative area and those with positive velocity contribute positive area.
Between t=0 s and 7 s,

Δx =


Homework Equations


Area of Rectangle: (l*w)
Area of Trapezoid: (1/2 b (h1+h2))
Area of Triangle: (1/2bh)
3. Rectangle: 1.5(-380)= -570
Trapezoid:1/2*3*(-380+-280)=-825
Triangle: 1/2*1.5*280=-420

delta x = -(570+825+420)= -1815 ...this was my attempt and it was wrong. I don't know what I am doing wrong please help

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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Could you elaborate on how you got your answer for delta x?
 
I used the points for t-0 and t-7 and came up with the three shapes on the graph..(the rectangle the trapezoid and the triangle) and then solved for their area under the curve and then combined.

I don't have a scanner to post the graph that I drew the shapes on.
 
You should be calculating the area between the curve and the horizontal axis where
v = 0.
 

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