Finding the E-field between two infinite plane charged sheets

AI Thread Summary
The discussion centers on calculating the electric field between two infinite, parallel charged sheets with surface charge densities of 13.35 µC/m² and -8.65 µC/m², separated by 0.245 m. The electric field is derived using the formula E = (σ1 + σ2) / (2 * ε₀), where ε₀ is the permittivity of free space. The calculation yields an electric field of -1.2 x 10^6 N/C, indicating the field direction is negative along the x-axis. Participants debate the significance of the direction of the electric fields due to each sheet and the importance of significant figures in their final answer. The consensus emphasizes that both sheets contribute negatively to the electric field, confirming the calculated result.
aximwolf
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Homework Statement



Two infinite-plane non-conducting, thin sheets of uniform surface charge p1 = 13.35 uC/m2 and p2 = -8.65 uC/m2) are parallel to each other and d = 0.245 m apart. (As shown in the diagram below.) What is the electric field between the sheets? (Note: the field is positive if it is parallel to the vector x).

prob18a.gif


Homework Equations



Sigma/2*epsilon_not

Epsilon not = 8.85e-12 (SI Units)

The Attempt at a Solution



The distance between the sheets should not matter in calculating the E-field between them because the E-field between them is uniform. We are given two sigmas and since the net charge on the field is toward the negative plane we just sum the two over 2*epsilon_not, and Epsilon not is a constant.

sigma1=13.35e-6 C/m^2
sigma2=-8.65e-6 C/m^2

(sigma1 + sigma2)/(2*epsilon_not) = E-field
(13.35e-6 + 8.65e-6)/(2*epsilon_not) = 1.2e6 N/C
Than since the E-field is perpendicular to the planes, but pointing in the opposite direction of positive X the answer becomes negative.
Answer: -1.2e6 N/C (unfortunately I tried this and did not get the problem right)

What did I get wrong?
 
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In the region between the sheets:
What is the direction of the E field due to the σ1 sheet?

What is the direction of the E field due to the σ2 sheet?​
 
The E-field on sigma1 is going -x and so is sigma2 right?
 
Is the marking software fussy about significant figures?
 
aximwolf said:
The E-field [STRIKE]on[/STRIKE] due to sigma1 is going -x and so is sigma2 right?

Right, so you should have a negative plus a negative.
 
Right but that doesn't change the answer numerically am I forgetting a step?
 
aximwolf said:
Right but that doesn't change the answer numerically am I forgetting a step?
Why did you express your answer to only 2 sig figs? (To repeat what gneill already pointed out.)
 
More sig figs worked thank you everyone!
 
aximwolf said:
Right but that doesn't change the answer numerically am I forgetting a step?
You have:
E-field due to sigma1=13.35e-6 C/m2
E-field due to sigma2=-8.65e-6 C/m2


But, if they're both pointing left (as vectors), then they should both be negative !

E1 + E2 = -13.35×10-6 + -8.65×10-6 = ____ ?
 
  • #10
yes that's the way I ended up doing it -13.35e-6+-8.65e-6
 
  • #11
That's stange, I don't see that result anywhere in this thread.
 
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