1. The problem statement, all variables and given/known data Find the equation, in standard form, of the normal line drawn to the graph of y=3x4 - 1/x at x = 1 2. Relevant equations 3. The attempt at a solution -I figured out the slope of the tangent to be 12x3 + 1, then at x = 1 the slope is 13 -SO the slope of the normal being the negative reciprocal of 13 led me to get -1/13 -Plug that into the y - y1 = m(x - x1) equation and I get x +13y - 27 = 0 for the equation of the normal. Im a little gun shy since the numbers seem abnormally large, so I would love if someone could verify this, or if im wrong, point me in the right direction of being right! Cheers.