Finding the Force of Nucleus on a Single Electron of Plutonium

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Homework Help Overview

The discussion revolves around calculating the force exerted by a plutonium nucleus on a single electron, given the number of protons and neutrons in the nucleus and the distance from the nucleus to the electron. The subject area includes concepts from electrostatics and atomic structure.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Coulomb's law but expresses confusion about which charge to use for a single electron versus the total charge of all electrons. Some participants suggest focusing on the charge of just one electron for the calculation.

Discussion Status

Participants are actively engaging with the problem, offering guidance on the correct application of Coulomb's law. There is a recognition of the need to clarify the roles of the charges involved in the calculation. Multiple interpretations of the problem setup are being explored, particularly regarding the charges of the nucleus and the electron.

Contextual Notes

There is an ongoing discussion about the proper use of mathematical notation in the forum, with participants seeking help on formatting equations correctly. The original poster also mentions that this is part of their exam preparation.

anomalocaris
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Homework Statement



A particular nucleus of the element Plutonium contains 94 protons and 150 neutrons. What is the magnitude of the force from the nucleus on a single electron that is a distance of 0.563x10-12 m from the Plutonium nucleus?

So basically this was a homework question that I got wrong, and I'm not entirely sure what the correct answer is. I'm reworking it to study for an exam, but I want to make sure this is right so I don't keep lousing it up!

Homework Equations



e=1.60x10-19 C
and F=kQ/r2
where k is Coulomb's constant 8.99x109 Nm2/C2

The Attempt at a Solution



Okay so if there are 94 protons, there should be 94 electrons.
(94)(e)=(94)(1.60x10-19 C)=1.5x10-17 C

Where I'm getting confused is what charge I should use to find the force? Because 1.5x10-17 C is the charge of all 94 electrons and I need the magnitude of the force of the nucleus on just one electron. I'm not quite grasping this concept.

Anyway, if I blindly plug in numbers without really understanding completely what I'm doing here, I get:

F=(k(1.5x10-17 C))/(0.563x10-12 m)2
so F=4.27x1017 N

Also, how do I type fractions on this forum? I found the button but I'm not sure where to enter my numbers so it works! Thanks!
 
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anomalocaris said:
and F=kQ/r2
You've left something out of that equation.
Okay so if there are 94 protons, there should be 94 electrons.
The problem asks for the force of the nucleus on a single electron. You can ignore the other 93 electrons.
 
Okay, so should I have used F=\frac{(k(q1)(q2))}(r<sup>2</sup>){}? And then I would use e as the charge of one electron (my q2) and the charge of all 94 electrons as my q1? Or am I completely off here? Thank you!
 
Oh, sorry, the fraction thing still is not working for me. I meant F=(k(q1q2))/(r^2)
 
anomalocaris said:
Okay, so should I have used F=\frac{(k(q1)(q2))}(r<sup>2</sup>){}? And then I would use e as the charge of one electron (my q2) and the charge of all 94 electrons as my q1? Or am I completely off here? Thank you!
That's the way to do it.
 
Oh! Yay! Thank you so much,tms! I really appreciate it!
 
anomalocaris said:
Oh, sorry, the fraction thing still is not working for me. I meant F=(k(q1q2))/(r^2)
You need to put the denominator in the second set of curly braces: \frac{(k(q1)(q2))}{(r2)}
F=\frac{(k(q1)(q2))}{(r2)}
You should also use subscripts and superscripts, and you can get rid of the extraneous parentheses: F=k\frac{q_1q_2}{r^2}
F=k\frac{q_1q_2}{r^2}
If you are planning to go further in math or science, it is worth learning LaTeX. You can google for some brief introductions and tutorials.
 
I tried doing that, but it didn't look right when I previewed it. My browser can be kind of wonky, though, so I'll keep trying. And I've never heard of LaTeX--sounds really cool. I'll definitely google that! Thanks again for all your help!
 

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