Finding the fourth root of 6.0 x 10

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To find the equilibrium constant for the reaction N <--> 0.5N2 from Kp = 6.0 x 10^8 for N2 <--> 2N, the fourth root of Kp is necessary. The attempted calculation of the fourth root did not yield the correct result, which should be 4.1 x 10^3. It is suggested to express the reaction quotients in terms of each other to solve the problem accurately. Understanding the relationship between the two reactions is crucial for deriving the correct equilibrium constant. The discussion emphasizes the importance of proper mathematical manipulation in equilibrium calculations.
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Homework Statement



If Kp = 6.0 x 108

For equilibrium N2 <--> 2N

Then what is the equilibrium constant of

N <--> .5N2

Homework Equations


K= C^c/A^a

The Attempt at a Solution



I tried finding the fourth root of 6.0 x 108 and that didn't give the right result. BTW the answer is 4.1 x 103, I'm just looking for the way to solve the problem.
 
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Write both reaction quotients, see if you can express one as a function of the other.

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