Finding the gradient to the curve using differentiation

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Homework Statement
Hello, I have been revising differentiation and calculus problems but I am rather struggling with the problem below;

The curve y=x^3-x+1 passes through the points P and Q, with x-coordinates of 1 and 1+h respectively.Using differentiation from first principles frind the gradient of the curve at P.
Relevant Equations
f'(x)=f(x+h)-f(x)/h
I have attached a photograph of my workings. I do not know if I have arrived at the right solution, nor whether this is the gradient of f(x) at point P.
I think I seem to overcomplicate these problems when thinking about them which makes me lose confidence in my answers. Thank you to anyone who replies 👍😁
 

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Looks good to me.
 
PeroK said:
Looks good to me.
Thank you for your reply, really splendid. I have really been trying to improve my understanding problems encompassing differentiation from first principles. 😁👍
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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