Finding the Height Function for y=\frac{-1}{X^2} + 4

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bayan
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Hi guys.

I was doing a SAC and there were two questions

one was y=\frac {1}{X^2}-1 and the other was y=\frac {-1}{X^2}+4

I got the hight function to be h=e^\frac{V}{\pi}-1 where V is the volume and max hight is 3 for the first function y=\frac {1}{X^2}-1

Can someone help me to find the hight function of the other function please.


The Volume of both graphs are same.


Thanx in advance.
 
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is this the hight function of second function? h=e^\frac{-V}{\pi}-4
 
would you mind defining a 'hight' function. I can find no references for it (other than misspelling it as height when it is defined for abelian groups according to planet math)
 
bayan said:
Hi guys.

I was doing a SAC and there were two questions

one was y=\frac {1}{X^2}-1 and the other was y=\frac {-1}{X^2}+4

y= \frac{1}{X^2}-1 is not a question- it is a function or equation. What was the question??

I got the hight function to be h=e^\frac{V}{\pi}-1 where V is the volume and max hight is 3 for the first function y=\frac {1}{X^2}-1

Can someone help me to find the hight function of the other function please.


The Volume of both graphs are same.


Thanx in advance.

I didn't know a graph had a volume! I assume "hight" was a misprint for "height" but I'm still not sure what you mean by the "height" of a function.
 
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HallsofIvy said:
y= \frac{1}{X^2-2}-1 is not a question- it is a function or equation. What was the question??



I didn't know a graph had a volume! I assume "hight" was a misprint for "height" but I'm still not sure what you mean by the "height" of a function.
Sorry about my BAD english but all I intended to say is how can I find the rate of change of height with respect to change in volume from the second equation.


Hope that makes it abit more clear.
 
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