Finding the Initial Speed for a Winning Putt at the U.S. Open

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Homework Help Overview

The problem involves calculating the initial speed required for a golf ball to complete a putt of 22.0 feet, given that an initial speed of 1.27 m/s results in the ball stopping 6.00 feet short. The context is rooted in kinematics and the effects of deceleration on the ball's motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to convert units and calculate time taken for the ball to travel a distance, but expresses confusion about how to proceed with finding the necessary initial speed. Some participants question the validity of the original poster's approach regarding constant velocity versus deceleration, suggesting the use of kinematic equations instead.

Discussion Status

Participants are exploring different interpretations of the problem, with some guidance offered on using kinematic equations to determine deceleration. The original poster has made several calculations but is unsure about the next steps, indicating a lack of consensus on the correct approach.

Contextual Notes

There are constraints related to the assumptions about constant deceleration and the need for accurate unit conversions. The original poster is also facing challenges with the mathematical implications of their calculations, particularly regarding the square root of a negative number.

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At the 18th green of the U. S. Open you need to make a 22.0 ft putt to win the tournament. When you hit the ball, giving it an initial speed of 1.27 m/s, it stops 6.00 ft short of the hole.


(a) Assuming the deceleration caused by the grass is constant, what should the initial speed have been to just make the putt?
m/s


(b) What initial speed do you need to just make the remaining 6.00 ft putt?
m/s

So far, to try and find the inital speed needed to make the putt, I have done the following.

1. 22 feet away from the hole, the putt is 6 feet short, so I subract 6 from 22, and I get 16 feet.

2. Now that I have 16 feet, I take the initial speed of 1.27 m/s and convert it to feet per second. I get 4.166666673 feet per second.

3. Now that both the feet away from the hole (16 feet) and the initial speed (4.166666673 ft/s) are in the same units, I divide them, to get the time it took for the golf ball to travel that distance. I get 3.839999994 or 3.84.

4. Now I am stumped, with these things I have figured out about the problem, how can I use this to find the inital speed I would need to just make the putt?

Time it takes golf ball to travel 16 feet away from the hole (3.84 seconds)
Total Distance = 22 Feet
Golf Ball = 6 feet short from hole

as for question (b) I am completely stumped. Any help would be greatly appreciated! Thank you!
 
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I don't think your step -3- is correct. The velocity is not constant, the deceleration is. Use the kinematic acceleration equation to tell you what the deceleration is in m/s^2.
 
the correct formula is Change in Velocity / Time correct? If So I have taken the change in velocity, I have taken 1.27 m/s and divided it by 3.84(the time taken for the ball to reach the hole)

This gives me the number .330729167 or, .3301

When I plug this into a position versus time graph, I get

xf=xi+viT+.5at^2

0=1.27+0+.5(.3301)t^2


0=1.27+.1653645833 or

0=1.27+.17t^2

now I subtract

0=1.27+.17t^2
-1.27

-1.27=.17t^2

t^2=-.1338582677 (or -.134)

but I cannot get the square root of -.134 on my calculator because it says ERROR: NON REAL ANSWER, so I am not sure where I messed up, but any help is still appreciated!
 
****Bump****
 

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