Finding the Integral using U-Substitution

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Homework Statement



Use the Integral Test to determine convergence or divergence of the series:

Ʃ ln(n)^-4
n=2


Homework Equations



Integral Test

d/dx ln(x)=1/x

f(x)=ln(x)^-4


The Attempt at a Solution



I understand how to apply the Integral test. I just am having a difficult time finding the integral of f(x).
I tried using u-substitution, where u=ln(x)

du=(1/x) dx

dx=xdu
When I try to plug in the substitutions for u and du, I am left with the improper integral
∫x/u^4 du from 2 to Infinity

Since the x is still in there, I can't continue with the substitution.

Is there another way to go about solving the integral? Am I approaching the u-substitution wrong?
 
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Broo4075 said:

Homework Statement



Use the Integral Test to determine convergence or divergence of the series:

Ʃ ln(n)^-4
n=2

Homework Equations



Integral Test

d/dx ln(x)=1/x

f(x)=ln(x)^-4

The Attempt at a Solution



I understand how to apply the Integral test. I just am having a difficult time finding the integral of f(x).
I tried using u-substitution, where u=ln(x)

du=(1/x) dx

dx=xdu
When I try to plug in the substitutions for u and du, I am left with the improper integral
∫x/u^4 du from 2 to Infinity

Since the x is still in there, I can't continue with the substitution.

Is there another way to go about solving the integral? Am I approaching the u-substitution wrong?

You can get rid of the x. If u=ln(x) then x=e^u. But you still can't integrate it, really. And you don't have to. You just have to figure out whether it converges or diverges. What happens to your integrand as u->infinity? And for some minor technical points you really should say why you can apply the integral test in the first place, and for a second one of your limits on the u integral is wrong. x goes from 2 to infinity. What are the limits for u?
 
Last edited:
so as u increases, the integral equals zero?

I know I can use the integral test because f(x) is continuous, positive, and decreasing from 2 to infinity.
 
Broo4075 said:
so as u increases, the integral equals zero?

I know I can use the integral test because f(x) is continuous, positive, and decreasing from 2 to infinity.

Good on justifying the use of the integral test. But my real point is that can you show that the limit of e^u/u^4 as u goes to infinity is infinity? Since the integral corresponds to area under the curve, the area under the curve must be infinity. So the integral will diverge. Even if you can't write an antiderivative for e^u/u^4, you will still know that.
 
oh okay, I see now. And since the Integral diverges, the series also diverges. Thank you so much. That helps explain quite a few problems that I have, but now they make sense
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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