Finding the Inverse Laplace Transformation

izen
Messages
50
Reaction score
0

Homework Statement



find the inverse laplace transformation of \frac{5s+4}{s^2} e^{-2s}

Homework Equations

The Attempt at a Solution



I have tried to partial fractions \frac{5s+4}{s^2} and I got \frac{5}{s}+\frac{4}{s^2} and I know that the answer must have u(t-2) because of second shifting ( a=2)

but I looked at the answer from this question is 5 u(t-2)(e^{4(t-2)} - e^{-(t-2)}).

I don't know how to get that answer please help
 
Physics news on Phys.org
The answer is wrong.
 
so my answer is [5+4(t-2)] u(t-2) Is my answer right?
thank you
 
izen said:

Homework Statement



find the inverse laplace transformation of \frac{5s+4}{s^2} e^{-2s}

Homework Equations




The Attempt at a Solution



I have tried to partial fractions \frac{5s+4}{s^2} and I got \frac{5}{s}+\frac{4}{s^2} and I know that the answer must have u(t-2) because of second shifting ( a=2)

but I looked at the answer from this question is 5 u(t-2)(e^{4(t-2)} - e^{-(t-2)}).

I don't know how to get that answer please help

First: what is the inverse Laplace transform of ##(5s+4)/s^2##? Next: worry about the effect of the factor ##e^{-2s}##.
 
izen said:
so my answer is [5+4(t-2)] u(t-2) Is my answer right?
thank you
Yes, that's correct.
 
Thanks you all
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top