Finding the Length of a Path on a 3D Graph

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To find the length of the hiking route on the 3D graph defined by z=f(x,y)=(cos y)-(cos x) from the origin to the point (4π, 0, 0) while maintaining the same elevation, integration is necessary to compute the arc length. The second part of the problem involves determining a minimal length route along the gradient, starting in the positive x direction, which may require finding upper and lower bounds if an exact solution is not feasible. The discussion highlights confusion about using the arc length formula versus the path on the graph, emphasizing the need for clarity in applying integration techniques. Participants seek guidance on these mathematical concepts, particularly in the context of an important assignment. Understanding the integration process is crucial for solving both parts of the problem effectively.
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z=f(x,y)= (cos y) - (cos x)

u are at the origin and want to hike to point (4pie,0,0). U want to get to 4pie,0,0 by hiking a route that alway keeps you at the same elevation. what is the length of this route?

I ploted the graph and I already know the route that will keep me at the same elevation from origin to 4pie,0,0 but how do I find the length of that route??

As for the second part

Your second route always moves along the gradient. Determine such a route of minimal lenght, assuming you start hiking in the positive x direction. What is the length? If you cannot find and exact answer, then determine an upper bound and a lower bound bbetween which the actual length must lie.

I have no clue on doing the second part.
I need some serious help because this will determine my final grade so be clear and help me as much as u can. Thanks
 
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it is an ec assigment that worth quite a lot, not a take home exam.

why do u have to use the arc formula? The path is not on the arc but on the path between the circle.

My teacher told me to do integration to get the answer. I haven't done differential equation yet so...

don't be shy with giving hints :wink:
 
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