Finding the Location of the 2nd Antinode in a Standing Wave at 4.10 Meters

[jamcintyre1]

Homework Statement

The 4th node of a standing wave occurs at a position of 4.10 meters. Where is the 2nd antinode?

Homework Equations

nodes occur at: x=n*(λ/2)
antinodes: x=(n+.5)*(λ/2)

The Attempt at a Solution

n=4??
4.1m=2λ→λ=2.05m
now n=2? x=(2+.5)*(λ/2)≈2.56m wrong!
x=1.54m

 

[PeterO]

Homework Statement

The 4th node of a standing wave occurs at a position of 4.10 meters. Where is the 2nd antinode?

Homework Equations

nodes occur at: x=n*(λ/2)
antinodes: x=(n+.5)*(λ/2)

The Attempt at a Solution

n=4??
4.1m=2λ→λ=2.05m
now n=2? x=(2+.5)*(λ/2)≈2.56m wrong!
x=1.54m

No answer to that question as it stands.

Was there any particular feature of the standing wave at position 0.00 metres?

 

[jamcintyre1]

I didn't get any more info. the solution has a sin graph I think with the 2nd antinode as the 2nd max which mazes sense, so 1.5*wavelength/2. But I can't figure out why the equation won't work. Thanks for your help btw. I'll take a look at you question.

 

[PeterO]

I didn't get any more info. the solution has a sin graph I think with the 2nd antinode as the 2nd max which mazes sense, so 1.5*wavelength/2. But I can't figure out why the equation won't work. Thanks for your help btw. I'll take a look at you question.

This standing wave ..

Is it on a string, fixed at one end at 0.00

Is the standing wave in an open pipe? An open pipe that runs form 0.00m to some distant point?

Is this standing wave in a stopped pipe? A stopped pipe with its stopped end at 0.00?