Finding the Magnitude of Normal Force

AI Thread Summary
The discussion focuses on calculating the centripetal force acting on a motorcycle moving at a constant speed over a hill. The centripetal force was correctly determined to be 2236.6 N using the formula Fc = mv²/r. For finding the normal force, participants suggest using a free body diagram to identify all acting forces, including gravitational force (mg). The net force equation, Fnet = m*acc, is emphasized to clarify the relationship between forces. Understanding these concepts is crucial for accurately determining the normal force in this scenario.
ny_aish
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A motorcycle has a constant speed of 30.0 m/s as it passes over the top of a hill whose radius of curvature is 134 m. The mass of the motorcycle and driver is 333 kg.

a)Find the magnitude of the centripetal force that acts on the cycle.
(I found the Centripetal force by Fc=mv^2/r which is 2236.6N)

b)Find the magnitude of the normal force that acts on the cycle.
( I thought they are asking for F=ma for this which is wrong... any help?,)
 
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Rather draw a free body diagram. The centripetal force you found is the net force.
 
So N = mg
 
How do you draw a free body diagram? List all the forces along their directions.
Then apply
Fnet = m*acc.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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