Finding the Masses of a binary star using the distance, angle and orbital period

AI Thread Summary
The discussion revolves around calculating the masses of two stars in a binary system with a 30-year orbital period and a distance of 20 parsecs. The angular radius of the orbit is given as 1", which was converted to radians for calculations. The user initially calculated the radius of the orbit to be approximately 1200 AU, leading to an implausibly high combined mass of 1,920,000 solar masses. Upon further reflection, the user realized a mistake in assuming 1" equated to 1', which significantly impacted the calculations. The conversation highlights the importance of accurate unit conversions in astrophysical calculations.
PaulWright
Messages
10
Reaction score
0

Homework Statement



Two stars are in a circular visual binary system. The orbital
period of the binary is 30 years. The distance to the binary is 20
parsecs. The angular radius of the orbit of each star is 1". What
are the masses of the two stars?

Homework Equations



I am assuming that the two stars are of the same mass.
\frac{a^3}{p^2}=2M

The Attempt at a Solution



as the angle is 1" this is 0.000290888209 radians

using the small angle approx opp/adj should = 0.000290888209 radians
we have adj, which is 20pc, therefore the opp (the radius of the orbit) should be 5.81776418*10^-3pc, which is 1200AU, which is therefore the distance between the two stars in AU, which is required for the equation.

therefore we get \frac{1200^3}{30^2}=M_1+M_2 which is 1920000 Solar masses, therefore each mass is 960000 Solar mass.

This seems way too big, and I would like someone to show me where I have gone wrong.

Cheers,
Paul
 
Last edited:
Physics news on Phys.org
1'' = 1/3600 degrees = 4.848 * 10^(-6) radians.
 
willem2 said:
1'' = 1/3600 degrees = 4.848 * 10^(-6) radians.

Jees, I never saw that I assumed 1"=1'

Cheers
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top