Finding the Median with Class Scores

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To find the median from a frequency table with class intervals, one should provide the class boundaries rather than just the midpoint of the median class. The example given illustrates that using class boundaries allows for a more accurate representation of the data, accommodating all possible scores within the ranges. The discussion highlights that if the class intervals are defined as inclusive of the lower boundary and exclusive of the upper boundary, it permits non-integer scores. Clarifying the boundaries ensures that all potential scores are considered in the analysis. Therefore, using class boundaries is the recommended approach for determining the median in this context.
danago
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If I am given a frequency table, but instead of set scores, i am given classes, or a range of scores. So for example:

20-29 | 11
30-39 | 12
40-49 | 2

etc.

If asked to find the median of the set of data, should i give the midpoint of the class containing the median score, or should i give the whole class. So in the example above, should i give 34.5, or 30-39?

Thanks in advance,
Dan.
 
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Think of some example sets of scores that fit your grouping. Do they all have median 34.5?
 
No they dont, so id give the class boundaries then?

Thanks,
Dan.
 
danago said:
No they dont, so id give the class boundaries then?

Thanks,
Dan.

I can't think what else you would do. BTW the class boundaries would suggest that all of the scores are integers.
 
Dick said:
I can't think what else you would do. BTW the class boundaries would suggest that all of the scores are integers.

How is that so? Why does it suggest all scores are integers?
 
danago said:
How is that so? Why does it suggest all scores are integers?

Because e.g. 39.5 is not in any range.
 
Oh i see. If i changed it to:

20 <= x < 29 | 11
29 <= x < 39 | 12
40 <= x < 49 | 2

Then that would allow for all scores within the boundaries, integers or not?
 
Yep. Right.
 
ok, thanks :smile:
 
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