Chemistry Finding the molecular formula of an unknown hydrocarbon

AI Thread Summary
The discussion revolves around determining the molecular formula of an unknown hydrocarbon using diffusion rates and Graham's law. The participant calculates the molar mass of the hydrocarbon to be approximately 44.18 amu, leading to the equation 12.011x + 1.008y = 44.18. They struggle with finding a second equation to solve for the unknowns x (C atoms) and y (H atoms), considering integer constraints for hydrocarbons. Suggestions include plotting possible combinations of x and y values and using a spreadsheet to identify feasible molecular formulas that match the calculated molar mass. The conclusion emphasizes the importance of considering physical constraints in addition to mathematical calculations when solving such problems.
zachary570
Messages
5
Reaction score
4
Homework Statement
In a given diffusion apparatus, 15.0 mL of HBr gas diffuses in 1.0 min. In the same apparatus and under the same conditions, 20.3 mL of an unknown gas diffuses in 1.0 min. The unknown gas is a hydrocarbon. Find its molecular formula.
Relevant Equations
Graham's law of effusion: ##\frac{rate_a}{rate_b} = \sqrt{\frac{M_b}{M_a}}##

Ideal Gas Law: ##PV = nRT##
Hello,

I am having some trouble finishing this problem from my textbook and would like some insight on the problem. We are looking for the molecular formula of a hydrocarbon. So, if we let x = number of C atoms and y = number of H atoms then we need to find ##C_xH_y##. From the problem statement we can find the rates of diffusion for both compounds:
$$rate_{HBr} = \frac{V}{t} = 15.0 \frac{mL}{min}$$

and

$$rate_{C_xH_y} = 20.3 \frac{mL}{min}$$

We know that the molar mass of HBr = 80.912 amu from the periodic table so we can use Graham's law to find the molar mass of the hydrocarbon.
$$\frac{rate_{HBr}}{rate_{C_xH_y}} = \sqrt{\frac{M_{C_xH_y}}{M_{HBr}}}$$

$$M_{C_xH_y} = M_{HBr} {\left(\frac{rate_{HBr}}{rate_{C_xH_y}}\right)}^2$$

$$M_{C_xH_y} = 80.912 amu {\left(\frac{15.0 \frac{mL}{min}}{20.3 \frac{mL}{min}}\right)}^2$$

$$M_{C_xH_y} = 44.17772817amu$$

So,
$$12.011x + 1.008y = 44.17772817$$

Here is where I am having trouble. I know that you need at least as many equations as you do unknowns to solve for them but I can't seem to find another equation. I thought using the ideal gas law, really Avogadro's Law, to find the number of moles in the apparatus. When I do that I get ##x + y = 1.353 moles## (assuming the initial n = 1) but this system gives a negative y value so it is clearly wrong. From the back of the book I know the answer should be ##C_3H_8##. If I were to just assume that the number of carbon atoms were as many as there could be then you get 3, from ##\lfloor \frac{44.17772817}{12.011} \rfloor##, and this gives the correct answer. But that doesn't feel like the right approach. If you assumed that there were only 2 carbon atoms then there would need to be 20 hydrogen atoms and the result would work just as well. Any advice on what I should be thinking about would be much appreciated.

Also, when googling this question the following video comes up. I used it to get to the point where I am now but I have two questions on their methods. (1) How did they know that ##rate = \frac{V}{t}##? I understand why it makes sense from what diffusion means but no such relation shows up in my textbook. I am using "Chemistry: A Molecular Approach, Fourth Edition by Nivaldo Tro" and the only relations given is that rate is inversely proportional to the square of molar mass as well as Graham's law when it discusses effusion and diffusion. I have looked it up and it seems to come from physics when dealing with liquids but I haven't learned that yet so how would I have known that without outside help? (2) When solving for x and y, she gets x as a function of y and then plugs that back into the original equation. The way she does it however seems to just be a rounding error. If she wouldn't have rounded then the expression would just be 58 = 58 which doesn't answer anything. Instead she uses it to solve for x and y. Isn't this wrong?

Thanks,
zachary570
 
Physics news on Phys.org
If it were just an algebra problem, then you have 1 equation and 2 unknowns. But there are constraints that x and y muat be positive integers.

If you plot the line and find which values of x & y are possible, that is how I would approach this.
 
To add to what @scottdave wrote: try to build a spreadsheet with every possible combination of reasonably looking formula for small hydrocarbons that have molar mass below 50. Say something like CxHy where x is between 1..4 and y between 4..8.

How many of them have molar mass that you calculated from the effusion data?
 
You can use your knowledge of molecular bonds to see whether each chemical formula that you found is possible.
 
scottdave said:
You can use your knowledge of molecular bonds to see whether each chemical formula that you found is possible.
Borek said:
To add to what @scottdave wrote: try to build a spreadsheet with every possible combination of reasonably looking formula for small hydrocarbons that have molar mass below 50. Say something like CxHy where x is between 1..4 and y between 4..8.

How many of them have molar mass that you calculated from the effusion data?
Thank you both for these responses as its cleared up my confusion for this problem. I guess I need to move away from thinking of these problems as purely a math exercise and consider the physical constraints. I now see why 2 carbons with 20 hydrogrens isn't a real answer and 3 and 8 is the only real one that satisfies the equation. All the other reasonable formulas have molar masses that are either less than or greater than 44amu.
 
  • Like
Likes Mayhem, scottdave and Borek
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top