Finding the Moment of a Force about a Point

  • Thread starter Thread starter sdoug041
  • Start date Start date
  • Tags Tags
    Moment Point
AI Thread Summary
To find the moment of force A about point D, the relevant equation is MD = rA/D × F, where r is the distance from A to D (27.5 cm) and F is the force acting on the object (49 N). The user is unsure how to determine the effective force acting on D and is considering using trigonometric functions based on an angle of 15 degrees. A response clarifies that the moment can be calculated by breaking the radius and force vectors into their components and using the cross product, which inherently includes the necessary trigonometric relationships. The user expresses relief at the simplicity of the solution after receiving guidance.
sdoug041
Messages
25
Reaction score
0

Homework Statement



I need to find the moment of A about D. We are given the Fg on the object to be 49N and the distance from A to D is 27.5cm. I've attached a drawing to help demonstrate.


Homework Equations



MD= rA/D X F

The Attempt at a Solution



I know the radius between A and D is 27.5cm but I'm not sure how to find out how much of the force is actually acting on D! I know I need to use sin or cos of a deduced angle (15 degrees or one relating to that). I'm not sure which trig operation or angle to use.

Would anyone be able to shed some light on how to go about? Much thanks.
 

Attachments

  • momentaboutd.jpg
    momentaboutd.jpg
    5.1 KB · Views: 513
Physics news on Phys.org
sdoug041 said:

Homework Statement



I need to find the moment of A about D. We are given the Fg on the object to be 49N and the distance from A to D is 27.5cm. I've attached a drawing to help demonstrate.


Homework Equations



MD= rA/D X F

The Attempt at a Solution



I know the radius between A and D is 27.5cm but I'm not sure how to find out how much of the force is actually acting on D! I know I need to use sin or cos of a deduced angle (15 degrees or one relating to that). I'm not sure which trig operation or angle to use.

Would anyone be able to shed some light on how to go about? Much thanks.

Welcome to the PF. The equation that you wrote is a vector equation, so you only need to write the vectors r and F, and take their cross product. The definition of the cross product includes the trig function that you need to use. Does that help?
 
Muchly appreciated I understand right now. Simply break the radius and force vector into it's components and cross. I knew it was easier than I thought; my frustration was unjustified!

Thanks man.
 
Thread 'Have I solved this structural engineering equation correctly?'
Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
Back
Top