Finding the number of molecules

  • Thread starter mawalker
  • Start date
  • #1
53
0
:confused:

Current vacuum technology can achieve a pressure of 1 * 10^-10 mm of Hg. At this pressure, and at a temperature of 30.0 C, how many molecules are in 5.00 cm3 ?

ok so atomic number of Hg = 80

80 * 1.661 * 10^-27 yields 1.33 * 10 ^-25 which is the mass of one molecule

converting from mm to atmospheres i get 1*10^-10 mm = 1.32 * 10 ^-13 atm since 760 mm = 1 atm

T = 303
5 cm3 = 5 ml = 5 * 10 ^ -3

so using pV = nRT
(1.32*10^-13)(5*10^-3) = n(.08206)pressure constant(303)
solving for n... n = 2.6459

n = M(in grams)/M of molecule so :
2.6459 = M/80
which gives me 211.67 grams....

N (number of molecules = M/m = .21167 Kg/1.33 * 10^-25 (mass of one molecule)

which yields me 1.59 * 10^ 24 molecules.... this answer is incorrect... any ideas?
 

Answers and Replies

  • #2
53
0
actually i think that i should be using 201 for the atomic number of mercury... this still ends up yielding 3.99 *10^24 which is still incorrect.
 
  • #3
53
0
actually, it yields 1.59 * 10^24....
 
  • #5
I'm not sure why you are going into mass of molecules... if you use PV=nRT, n is the number of moles. You can convert directly from moles to molecules using good ole 6.02E23. According to the IDEAL GAS LAW, the same number of moles of a gas ALWAYS occupy the same volume... regardless of WHAT the gas is.
 
  • #6
dextercioby
Science Advisor
Homework Helper
Insights Author
13,070
637
Incidentally, Hg (mercury) is a metal, and with metals we never speak about "molecules". In this problem it instructve to use the van der Waals state law, too and compare the 2 results.

Daniel.
 

Related Threads on Finding the number of molecules

  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
10
Views
2K
Replies
9
Views
2K
Replies
1
Views
2K
Replies
3
Views
1K
Replies
1
Views
943
Replies
0
Views
3K
  • Last Post
Replies
9
Views
4K
  • Last Post
Replies
1
Views
959
Top