Finding the probability of an electron

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Homework Help Overview

The discussion revolves around determining the probability of finding an electron in a specific region defined by the negative psi 320 wavefunction, particularly in a toroidal region. The subject area is quantum mechanics, focusing on wavefunctions and probability distributions.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of the roots of cos(theta) and their relation to the angular part of the wavefunction. Questions arise about the role of the radial part and whether it can be negative, as well as the nature of the wavefunction itself.

Discussion Status

The discussion is active, with participants questioning the relationship between the radial and angular components of the wavefunction. Some guidance has been offered regarding the positivity of probability and the need to examine the functional form of the wavefunction.

Contextual Notes

Participants note that the quantities discussed are squares of the relevant factors of the wavefunction and mention normalization concerns. There is an emphasis on the constraints that probability values must remain between 0 and 1.

apott155
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Homework Statement



Determine the probability of finding the electron in the region for which the psi 320 wavefunction is negative(toroidal region).

Homework Equations





The Attempt at a Solution


cos (theta)=+/- sqrt 1/3

radial part integrated= r^6*e^(-2r/3a)

Angular part= (9cos(theta)^4-6cos(theta)^2+1)sin(theta)
 
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Can you use the roots cos (theta)=+/- sqrt 1/3 to determine a range of [tex]\theta[/tex] for which the angular part of the wavefunction is negative?
 
YUp.
 
I tried that, but I don't see where the radial part comes in
 
Can the radial part of the wavefunction ever be negative? Note that the quantities you wrote down are the squares of the relevant factors of the wavefunction. (they're also not normalized).
 
I don't think so... The ending value has to be inbetween 0 and 1 because its probability
 
apott155 said:
I don't think so... The ending value has to be inbetween 0 and 1 because its probability

Be careful. [tex]|\Psi|^2[/tex] is positive and bounded, but [tex]\Psi[/tex] itself isn't so restricted. In this case you need to examine the functional form.
 

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