Finding the pushing force needed to keep object from sliding down wall

AI Thread Summary
To determine the pushing force needed to prevent a book from sliding down a wall, the calculations involve the book's weight and the coefficient of static friction. The weight of the book is calculated as 28.2N, and the force of static friction is expressed as μsN. By setting the normal force equal to the required pushing force, the equation F = (mg/μs) leads to a calculated force of 87.6N. This value is confirmed to be reasonable since it must exceed the weight of the book due to the static friction coefficient being less than one. Overall, the reasoning and calculations for the required force are deemed correct.
Timebomb3750
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This problem has been bugging me, seeing that my answer seems off. But who knows. Given the following measurements, find the required pushing force needed to keep a book from sliding down the wall.

Homework Statement


M= 2.88kg
Coefficient of static friction= .322

Homework Equations


Seeing that the book can't move, I figured that F=Normal force
mg=2.88kg(9.80 m/s^2)=28.2N
force of static friction=μsN

ƩFx=F-N=0
meaning F=N (Makes sense)

ƩFy=mg-fs=0
meaning mg=μs(N)
thus, N=(mg/μs)

The Attempt at a Solution


I did a simple substitution by setting F=(mg/μs)=(28.2N/.322)=87.6N

To me, that answer seems a little high. So, is my reasoning and/or answer correct?
 
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The answer must be greater in magnitude than the weight of the book because friction coefficient < 1. Your answer looks good to me.
 
LawrenceC said:
The answer must be greater in magnitude than the weight of the book because friction coefficient < 1. Your answer looks good to me.

That's good to know. Thanks.
 
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