Finding the Ratio of a Vector Division: Vector Equation Help

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The discussion revolves around finding the coordinates of point N that divides vector AM in a 2:1 ratio. The vector equation provided is r = (0,0,6) + x(0,-4,-6), leading to confusion over the value of x. Participants initially agree that x should be 2/3, but one contributor insists the correct answer is 9/13, causing confusion. The suggestion is made to solve the equation (r-A)^2=2^2*(r-M)^2 for clarity. Ultimately, the disagreement highlights the complexity of vector division and the importance of verifying calculations.
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'Write Down the vector AM and hence the coords of the point N which divides AM so that the ratio AN:NM = 2:1.'

I know that ON = OA + AN

And that the vecor equation is

r = (0,0,6) + x(0,-4,-6)

But the answer is 9/13 for x, which i don't understand. I thought it would be 2/3 or 2/3 of the length AM. I am really stuck.

Thanks
 
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Just take (r-A)^2=2^2*(r-M)^2 and solve for x. Or just notice x=0 gives A and x=1 gives M so the x that splits it 2:1 must be 2/3.
 
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so ur saying x = 2/3?

thats what i said, but the answer says its 9/13 which i don't understand.
 
Firepanda said:
so ur saying x = 2/3?

thats what i said, but the answer says its 9/13 which i don't understand.

If I'm understanding the question, yes, I say x=2/3.
 
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