touqra
- 284
- 0
How do you get the residue of this expression:
\frac{1}{(e^z - k)} where k is a constant.
\frac{1}{(e^z - k)} where k is a constant.
The discussion focuses on calculating the residue of the expression \( \frac{1}{(e^z - k)} \), where \( k \) is a constant. It emphasizes that if \( k = 0 \), the expression becomes \( \frac{1}{e^z} \), which is analytic. However, for \( k \neq 0 \), the expression introduces a singularity that is contingent upon the chosen contour for integration. Understanding the behavior of this expression is crucial for complex analysis applications.
PREREQUISITESStudents and professionals in mathematics, particularly those specializing in complex analysis, as well as physicists and engineers dealing with integrals involving exponential functions.
touqra said:How do you get the residue of this expression:
\frac{1}{(e^z - k)} where k is a constant.