Finding the resulant from the product

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To determine the empirical and molecular formula of limonin, start by converting the combustion products' masses of CO2 and H2O into moles. The total mass of products exceeding the original sample weight is due to the addition of atmospheric oxygen during combustion, which is not accounted for in the initial mass. Calculate the molar ratios of carbon, hydrogen, and oxygen from the moles of CO2 and H2O produced. Divide these values by the smallest mole quantity to obtain integer ratios, which will lead to the empirical formula. Finally, use the molar mass of limonin to derive the molecular formula from the empirical formula.
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I am new to Chem, and I don't quite understand how to solve this problem:

Component of citrus fruits is the bitter compound limonin, which contains only carbon, hydrogen, and oxygen. When a 1.000-gram sample of limonin is subjected to complete combustion, 2.432 grams of CO_2 and 0.574 grams of H_2O are producted. In addition, the molar mass of limonin is approximately 475 g/mol. Detrmine the emprirical formula and molecular fomrula of limonin.

I don't get how can you have a total of about 3gram for the product, whereas the resulatant is only 1gram? I thought the mass has to be equal throughout the problem
 
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atmospheric oxygen.
 
leolaw said:
I don't get how can you have a total of about 3gram for the product, whereas the resulatant is only 1gram? I thought the mass has to be equal throughout the problem

that is the whole point of the problem. you need to find the molar ratios to determine the formula for the limonin, and you need the masses to do this. once your molar ratios are balanced then the masses will work out.

so convert all of your masses into moles. divide them all by the lowest one to get integer values: these should be your molar ratios.
 
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