Finding the slop of a string (Waves)

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To find the slope of a transverse wave described by the equation y(x,t) = Asin(kx - ωt), the derivative dy(x,t)/dx must be calculated. The correct approach involves applying the chain rule, treating x as the variable and t as a constant. The derivative yields dy(x,t)/dx = A*cos(kx - ωt) * k, indicating that the term involving ωt should not be included in the derivative. The discussion emphasizes the importance of correctly identifying variables and constants when differentiating wave equations.
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Homework Statement



Wave motion is characterized by two velocities: the velocity with which the wave moves in the medium (e.g., air or a string) and the velocity of the medium (the air or the string itself).

Consider a transverse wave traveling in a string. The mathematical form of the wave is

y(x,t) = Asin(kx - \omega t)

Find the slope of the string \frac{dy(x,t)}{dx} as a function of position x and time t.

Homework Equations





The Attempt at a Solution



So to find the slope of that equation, I would just need to take it's derivative. x is the variables, and \omega, A, t are constants. I would also need to use the chain rule when doing the derivative of sin.

So I get: \frac{dy(x,t)}{dx} = (Acos(kx - \omega t))*(k - \omega t)

but it says I'm wrong. Any suggestions where I went wrong?
 
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Check your result for consistency of units.
 
\frac d {dx} ( kx- \omega t) = ?
 
Integral said:
\frac d {dx} ( kx- \omega t) = ?

would I treat the x as a variable and t as a constant?
 
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