Finding the slope and intercept of a graph

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The discussion revolves around finding the slope and intercept of a graph where ln(A) is plotted against ln(3d²). The equation ln(A) = ln(Bt) - ln(3d²) is key to understanding the relationship between the variables. By defining x as ln(3d²) and y as ln(A), the equation can be rewritten in a linear form, making it easier to identify the slope and intercept. The slope represents the relationship between the changes in A and d, while the intercept relates to the constant B in the equation. Clarifying these points aids in solving the problem effectively.
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Homework Statement


I am given the formula A = Bt / (3d2)

d is what we changed, A is what was measured.

I had to plot ln(A) vs ln(3d2).

What do the slope and intercept of this graph represent?

Homework Equations





The Attempt at a Solution


ln (A) = ln (Bt / 3d2) = ln(Bt) - ln(3d2)

ln (A) / ln (3d2) = ln (Bt)/ln(3d2) - 1

After this I get stuck. Help please!
 
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jumbogala said:

The Attempt at a Solution


ln (A) = ln (Bt / 3d2) = ln(Bt) - ln(3d2)

ln (A) / ln (3d2) = ln (Bt)/ln(3d2) - 1

After this I get stuck. Help please!

If you are plotting ln(A) vs. ln(3d2), then let

x = ln(3d2)
y = ln(A)​

and you are now plotting y vs. x.

Write your equation,

ln (A) = ln(Bt) - ln(3d2),​

in terms of x and y. The slope and intercept should become easier to identify.
 
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