Finding the speed of a bullet via device with two rotating disks

AI Thread Summary
The discussion revolves around calculating the speed of a bullet using a device with two rotating disks, separated by 0.879 m and rotating at 96.1 rad/s. The bullet passes through both disks, creating an angular displacement of 0.161 rad between the holes. Participants seek clarification on the arrangement of the disks and the equations involved, emphasizing the need for a sketch to visualize the setup. Key equations mentioned include angular displacement and relationships between distance, time, and speed. The conversation focuses on how to effectively use the provided data to derive the bullet's speed.
TmrK
Messages
21
Reaction score
0

Homework Statement


The device consists of two rotating disks, separated by a distance of d = 0.879 m, and rotating with an angular speed of 96.1 rad/s. The bullet first passes through the left disk and then through the right disk. It is found that the angular displacement between the two bullet holes is θ = 0.161 rad. From these data, determine the speed of the bullet.

Basically, I'm lost in this equation.
 
Physics news on Phys.org
What do you mean left disk, then right disk? How are the disks arranged? Are they both turning on the same shaft one behind the other? A sketch would be informative. Also, please show what equations you are working with.
 
θ=s/r & w=Δθ/Δt & α=Δω/Δt
 

Attachments

  • ch08p_13.gif
    ch08p_13.gif
    3.6 KB · Views: 577
OK, let's get started thinking about this problem.

What do you know about distance, time, and speed? How are they related mathematically?

You know how fast the disks are turning and therefore know how long it takes to make one complete revolution. You know how much the disks turned between bullet holes. You know the distance between the disks.

This data can be related to determine the speed of the bullet. Let's see how you put it all together to solve the problem.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top