Finding the speed of car A and car B

  • Thread starter Thread starter meeklobraca
  • Start date Start date
  • Tags Tags
    Car Speed
AI Thread Summary
The discussion focuses on determining the speeds of race cars A and B, given their relative velocity and acceleration. The relative velocity is noted as 1 ft/s, while the relative acceleration of car A with respect to car B is 0.9 ft/s² directed toward the center of curvature. Attempts to solve the problem using equations for circular motion and relative acceleration have led to an unsolvable quadratic equation. The key insight is that both cars must have the same angular velocity due to their constant speeds. The final step involves using the relationship between acceleration and velocity to find the individual speeds of the cars.
meeklobraca
Messages
188
Reaction score
0

Homework Statement



At the instant shown, race car A is passing race car B with a relative velocity of 1ft/s. Knowing that the speed of both cars are constant and that the relative acceleration of car A with respect to Car B is 0.9ft/s^2 directed toward the center of curvature, determine the speeds of cars A and B.

The diagram is located here: Problem 134

http://www.smccd.net/accounts/enriquez/Engr240Files/Problemset3.pdf

Thank you!



Homework Equations





The Attempt at a Solution



With the relative acceleration being what it is in the j direction, I plugged in 0.9 = vb^2/p - va^2/p and plugged in a 3+Va for vb. That doesn't work. What should I do here?

Thanks!
 
Physics news on Phys.org
Acceleration of the car in a circular motion is
a = v^2/r. Or
a*r = V^2.
So for larger radius acceleration is smaller. For car A
a*r(a) = V^2...(1)
For car B
(a - 0.9)r(b) =(V+3)^2...(2)
Solve the two equations.
 
doing that I get an unsolvable quadratic...
 
The two cars are moving together with constant velocity. So they must have the same angular velocity.
The acceleration a = ω^2*r.
So (a + 0.9) = ω^2*300
and a = ω^2*290. Now solve for a.
Then use a = V^2/r to find velocities of the cars.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top