Finding the Spring Constant for a Mass on a Spring System

  • Thread starter Thread starter anti404
  • Start date Start date
  • Tags Tags
    Mass
Click For Summary

Homework Help Overview

The discussion revolves around determining the spring constant for a mass-spring system, where a total mass of 100g is used to stretch a spring by 12cm. The original poster attempts to apply Hooke's Law but expresses uncertainty about the correct application of the masses involved.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relevance of the spring's mass in the calculations and question whether it should be included when determining the spring constant and the period of oscillation. There is also a focus on the equilibrium state of the system.

Discussion Status

Some participants have provided guidance on the calculations, suggesting that the mass of the spring may not be necessary for the spring constant determination. However, there remains some confusion regarding the inclusion of the spring's mass when calculating the period of oscillation.

Contextual Notes

Participants are navigating the constraints of the problem, including the need for clarity on how to handle the mass of the spring and the definitions of equilibrium in the context of the problem.

anti404
Messages
20
Reaction score
0

Homework Statement


A mass attached to a holder hangs from a spring. the combined mass of the hanger, spring, and mass=45g. Adding mass of 55g stretches the spring 12cm. What is the spring constant?


Homework Equations


Hooke's Law
F=kx


The Attempt at a Solution


(m1+m2)g/x=k
(.045kg+.055kg)9.8m/s^2/m = k
but this isn't right, I don't think.

I'm not sure what I'm missing, but it seems that I don't have all the information correctly utilized. Hooke's law, though, is the only thing I could think to use with the given information and based upon what we need to find.
any help would be greatly appreciated, as I need this information for my laboratory experiment.
 
Physics news on Phys.org
The mass of the spring do not need to be used as stretching with 55g stretches from the equilibrium state (the equilibrium state holes the 45g from the spring and system)
 
inutard said:
The mass of the spring do not need to be used as stretching with 55g stretches from the equilibrium state (the equilibrium state holes the 45g from the spring and system)

okay, so the mass of the spring etc. isn't used, and mg/x=K=4.49N/m.
then to find the period of oscillation when ALL masses are attached, T=2pi[sqroot(m/k)].
now when it says all the masses are attached, would you still not include the spring? I'm confused because it says something about having the spring adjusted 1/3 or something for its mass.

thanks,
Justin
 
Your work looks right. The mass for the period should be 55g.
 

Similar threads

Replies
17
Views
2K
Replies
20
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
1K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
20
Views
3K
  • · Replies 1 ·
Replies
1
Views
8K