Finding the Spring Constant for Bungee Jumping

AI Thread Summary
To find the spring constant for bungee jumping, the user needs to apply Hooke's Law (F = -KX) and the relationship between gravitational potential energy (GPE) and elastic potential energy (EPE). Given a weight of 735N and the rope doubling in length during the jump, the challenge is to determine the spring constant (K) without knowing the rope's initial length. The user attempts to equate the potential energy stored in the spring to the gravitational potential energy, leading to the equation 2mg = -kx. This approach highlights the need to rearrange the equations to solve for K in terms of the known variables.
wangking
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Homework Statement


Hey, i need some help here
I'm trying to figure out the spring constant for bungee jump

Say, I'm 735N and the rope will apparently double in length when i jump off it.
I don't know the length of the rope thought.
but i do know it does have a spring constant.
we are trying to find its N/m ratio.
How to find out is the spring constant using the Hooke's Law F=-KX

Please help :)


Homework Equations


F=-KX
EPE=1/2KX^2
EPE=GPE
mgh=1/2kx^2


The Attempt at a Solution



i can't find the spring constant
 
Physics news on Phys.org
Fall of potential - mgx.
PE stored in the spring is 1/2kx^2
-mgx = 1/2kx^2
2mg = -kx
 

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