The object starts from rest with no speed, and when it reaches the bottom, it momentarily stops and also has no speed. But there is gravitational potential energy at the top, and spring potential energy at the bottom.zachmgilbert said:i have .5mv2=.5kx2 but i don't know how to find velocity.
The stopping point of a falling mass on a spring is the point at which the spring reaches equilibrium, meaning that the restoring force of the spring is equal to the force of gravity pulling the mass down.
The stopping point can be calculated using the equation F = kx, where F is the force of the spring, k is the spring constant, and x is the displacement of the mass from its equilibrium position. When F = mg (force of gravity), the mass will reach its stopping point.
The stopping point is affected by the spring constant, the mass of the object, and the initial displacement of the mass from its equilibrium position. The stiffer the spring (higher spring constant), the higher the stopping point will be. A heavier mass will also result in a higher stopping point, while a larger initial displacement will result in a lower stopping point.
Yes, the stopping point can be changed by altering the factors that affect it. For example, the spring constant can be changed by using a different type of spring, or the mass and initial displacement can be adjusted to achieve a desired stopping point.
Knowing the stopping point is important in understanding the behavior of objects under the influence of forces, such as gravity and spring forces. It can also be useful in practical applications, such as designing and calibrating springs for suspension systems or determining the maximum weight a spring can support.