Finding the Taylor Series of f(x) = x/(2+x)

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Homework Statement


Obtain the Taylor series in powers of x + 1 for f(x) = x/(2 + x), giving
the general term.


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The Attempt at a Solution



Wrote it out as x*(1/1-(-(x+1)).
 
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If
<br /> f(x)=\frac{x}{x+2}<br />
We are asked to write it as a series in y=x+1, so in terms of y, the function becomes:
<br /> F(y)=\frac{y-1}{y+1}<br />
Now use all your previous knowledge about Taylor series to find the expansion in terms of y
 
hmm.. confused
 
OK, write your function as the following:
<br /> f(x)=\frac{x}{x+2}=\frac{(x+1)-1}{(x+1)+1}<br />
Use all the previous knowledge you have to find the taylor series.
 
Or you could write:
<br /> f(x)=\frac{x}{x+2}=\frac{x+2-2}{x+2}=1-\frac{2}{x+2}=1-\frac{2}{(x+1)+1}<br />
If that makes it easier.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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