Finding the Taylor Series of f(x) = x/(2+x)

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Homework Help Overview

The problem involves finding the Taylor series expansion of the function f(x) = x/(2 + x) around the point x = -1. Participants are tasked with expressing the function in terms of a new variable y = x + 1.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss rewriting the function in different forms to facilitate the Taylor series expansion. Some express confusion about the process, while others suggest various algebraic manipulations to clarify the function's structure.

Discussion Status

The discussion includes multiple approaches to rewriting the function for series expansion. Some participants have offered alternative forms of the function, while others are seeking clarification on the steps involved. There is no explicit consensus yet on the best method to proceed.

Contextual Notes

Participants are working under the constraint of expressing the function as a series in terms of y = x + 1, which may affect their approaches and reasoning.

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Homework Statement


Obtain the Taylor series in powers of x + 1 for f(x) = x/(2 + x), giving
the general term.


Homework Equations





The Attempt at a Solution



Wrote it out as x*(1/1-(-(x+1)).
 
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If
[tex] f(x)=\frac{x}{x+2}[/tex]
We are asked to write it as a series in [tex]y=x+1[/tex], so in terms of y, the function becomes:
[tex] F(y)=\frac{y-1}{y+1}[/tex]
Now use all your previous knowledge about Taylor series to find the expansion in terms of y
 
hmm.. confused
 
OK, write your function as the following:
[tex] f(x)=\frac{x}{x+2}=\frac{(x+1)-1}{(x+1)+1}[/tex]
Use all the previous knowledge you have to find the taylor series.
 
Or you could write:
[tex] f(x)=\frac{x}{x+2}=\frac{x+2-2}{x+2}=1-\frac{2}{x+2}=1-\frac{2}{(x+1)+1}[/tex]
If that makes it easier.
 

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