- #1
Jessica8956
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1. Finding tension force and torque (details attached)
http://imgur.com/cZLG9xP
2. please see attachment
http://imgur.com/cZLG9xP
3.
For part 1). I get
[itex]{T} = -\sin \alpha(i) +\cos \alpha(j)[/itex]
is this correct?
(Where T is the tension force)
For part 2). I am stuck .
What I did was get
[itex]{W} = -mgj[/itex]
Then get the position vector as
[itex]\frac{1}{2}2L\sin \alpha(i) \sin \alpha(j)[/itex]
Simplifies to
[itex]L\sin \alpha(i) \sin \alpha(j)[/itex]
So the answer is
[itex]-mgL\sin \alpha(k) [/itex]
Is this correct or am I completely off? Also will the end answer contain [itex] \alpha[/itex] or [itex] \theta[/itex]?
Thanks (not sure if I can chat here but great forum and hello as I'm new here)
http://imgur.com/cZLG9xP
2. please see attachment
http://imgur.com/cZLG9xP
3.
For part 1). I get
[itex]{T} = -\sin \alpha(i) +\cos \alpha(j)[/itex]
is this correct?
(Where T is the tension force)
For part 2). I am stuck .
What I did was get
[itex]{W} = -mgj[/itex]
Then get the position vector as
[itex]\frac{1}{2}2L\sin \alpha(i) \sin \alpha(j)[/itex]
Simplifies to
[itex]L\sin \alpha(i) \sin \alpha(j)[/itex]
So the answer is
[itex]-mgL\sin \alpha(k) [/itex]
Is this correct or am I completely off? Also will the end answer contain [itex] \alpha[/itex] or [itex] \theta[/itex]?
Thanks (not sure if I can chat here but great forum and hello as I'm new here)
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